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Question 4. (i) If 2x + 1 is a factor of 2x 2 + ax – 3, find the value of a. (ii) Find the value of k, if 3x – 4 is a factor of expression 3x 2 + 2x – k. Solution: Question 5. Find the values of constants a and b when x – 2 and x + 3 both are the factors of expression x 3 + ax 2 + bx – 12. Solution:p(-1) = (-1) 3 - 3(-1) 2 - 9(-1) - 5 = -1 - 3 + 9 - 5 = -9 + 9 = 0. Since the remainder of p(-1) = 0 , by factor theorem we can say x + 1 is a factor ofp(x) = x 3 - 3x 2 - 9x - 5. Now dividing p(x) by x + 1 using long division. Hence x 3 - 3x 2 - 9x - 5 = (x +1) (x 2 - 4x - 5) Now taking x 2 - 4x - 5, find two numbers p, q such that: p + q = -4 ...Quiz Polynomial 2x2 −3x−5 Similar Problems from Web Search 2x2 − 3x − 5 http://www.tiger-algebra.com/drill/2x~2-3x-5/ 2x2-3x-5 Final result : (2x - 5) • (x + 1) Step by step solution : Step 1 :Equation at the end of step 1 : (2x2 - 3x) - 5 Step 2 :Trying to factor by splitting the middle term ... 2x2 − 3x = −7 2x2-9x-5=0 Two solutions were found : x = -1/2 = -0.500 x = 5 Step by step solution : Step 1 :Equation at the end of step 1 : (2x2 - 9x) - 5 = 0 Step 2 :Trying to factor by splitting the ... 2x2-9x-11 Final result : (2x - 11) • (x + 1) Step by step solution : Step 1 :Equation at the end of step 1 : (2x2 - 9x) - 11 Step 2 :Trying to factor by ...Factor 2x^3+3x^2-2x-3. Step 1. Factor out the greatest common factor from each group. Tap for more steps... Step 1.1. Group the first two terms and the last two terms. rearrange equation into standard form. ⇒ 2x2 +3x − 5 = 0 ← in standard form. factor the quadratic using the a-c method. the factors of - 10 which sum to + 3 are …Algebra. Find the Roots (Zeros) y=2x^2+3x-5. y = 2x2 + 3x − 5 y = 2 x 2 + 3 x - 5. Set 2x2 +3x− 5 2 x 2 + 3 x - 5 equal to 0 0. 2x2 + 3x−5 = 0 2 x 2 + 3 x - 5 = 0. Solve for x x. Tap for more steps... x = 1,−5 2 x = 1, - 5 2. Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework ... Answer link. 2x^2-3x-9 = (2x+3) (x-3) The rule to factorise any quadratic is to find two numbers such that "product" = x^2 " coefficient "xx" constant coefficient" "sum" \ \ \ \ \ \ = x " coefficient" So for 2x^2-3x-9 we seek two numbers such that "product" = (2)* (-9) = -18 "sum" \ \ \ \ \ \ = -3 So we look at the factors of -18.2x 2-3x -5 =0 Factor to get (2x -5) (x + 1) =0 then. 2x - 5 = 0 and x = 2.5 x + 1 = 0 and x = -1 These are the x intercepts. B: As the coefficient of the x^2 term is positive, the parabola open up, and the vertex is a minimum. The coordinates of the parabola are given by -b/2a, f( -b/2a) where a and b represent the coefficients of a parabola in ...2x2 − 3x −5 = (2x − 5)(x + 1) = 0 ⇒ x = −1, 5 2. Answer link. x=-1,5/2 Factor the equation, note that both 2 and 5 are prime numbers, therefore they can only have themselves and 1 as a factor. Therefore a factorisation of: 2x^2-3x-5= (2x-a) (x-b)=0 Is likely. With either (absa,absb)= (1,5), (5,1) By inspection we see a=5,b=-1 ...Algebra. Factor 3x^2-2x-1. 3x2 − 2x − 1 3 x 2 - 2 x - 1. For a polynomial of the form ax2 +bx+ c a x 2 + b x + c, rewrite the middle term as a sum of two terms whose product is a⋅c = 3⋅−1 = −3 a ⋅ c = 3 ⋅ - 1 = - 3 and whose sum is b = −2 b = - 2. Tap for more steps... 3x2 + x−3x−1 3 x 2 + x - 3 x - 1. Factor out the ...Free Pre-Algebra, Algebra, Trigonometry, Calculus, Geometry, Statistics and Chemistry calculators step-by-step4x2+3x-1 Final result : (4x - 1) • (x + 1) Step by step solution : Step 1 :Equation at the end of step 1 : (22x2 + 3x) - 1 Step 2 :Trying to factor by splitting the middle term ... Find the value of a and b so that f (x) = 8x4 + 14x3 − 2x2 + ax + b is exactly divisible by g (x) = 4x2 + 3x − 2. Could anyone clarify the confusion described ...1 Answer Jim G. Mar 26, 2018 (x −1)(2x +5) = 0 Explanation: rearrange equation into standard form ⇒ 2x2 +3x − 5 = 0 ← in standard form factor the quadratic using the a-c method the factors of - 10 which sum to + 3 are + 5 and - 2 2x2 − 2x +5x −5 = 0 ← split the middle term 2x(x − 1)+5(x − 1) = 0 ← factor by grouping take out a common factor (x −1)2x2+3x-35=0 Two solutions were found : x = -5 x = 7/2 = 3.500 Step by step solution : Step 1 :Equation at the end of step 1 : (2x2 + 3x) - 35 = 0 Step 2 :Trying to factor by splitting ... 2x^2-3x-65=0How to factor expressions. If you are factoring a quadratic like x^2+5x+4 you want to find two numbers that. Add up to 5. Multiply together to get 4. Since 1 and 4 add up to 5 and multiply together to get 4, we can factor it like: (x+1) (x+4)Algebra. Solve by Factoring x^2-2x-5=0. x2 − 2x − 5 = 0 x 2 - 2 x - 5 = 0. Use the quadratic formula to find the solutions. −b±√b2 −4(ac) 2a - b ± b 2 - 4 ( a c) 2 a. Substitute the values a = 1 a = 1, b = −2 b = - 2, and c = −5 c = - 5 into the quadratic formula and solve for x x. 2±√(−2)2 −4 ⋅(1⋅−5) 2⋅1 2 ± ...Algebra. Solve by Factoring 2x^2+3x-20=0. 2x2 + 3x − 20 = 0 2 x 2 + 3 x - 20 = 0. Factor by grouping. Tap for more steps... (2x−5)(x +4) = 0 ( 2 x - 5) ( x + 4) = 0. If any individual factor on the left side of the equation is equal to 0 0, the entire expression will be equal to 0 0. 2x−5 = 0 2 x - 5 = 0.Algebra. Solve by Factoring 2x^2-3x=0. 2x2 − 3x = 0 2 x 2 - 3 x = 0. Factor x x out of 2x2 −3x 2 x 2 - 3 x. Tap for more steps... x(2x−3) = 0 x ( 2 x - 3) = 0. If any individual factor on the left side of the equation is equal to 0 0, the entire expression will be equal to 0 0. x = 0 x = 0. 2x−3 = 0 2 x - 3 = 0.Algebra. Factor 4x^2-3x+5. 4x2 − 3x + 5 4 x 2 - 3 x + 5. 4x2 − 3x+5 4 x 2 - 3 x + 5. Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor.

Use the function f(x) = 2x 2 − 3x − 5 to answer the questions.. Part A: Completely factor f(x). (2 points) Part B: What are the x-intercepts of the graph of f(x)? Show your work. (2 points) Part C: Describe the end behavior of the graph of f(x). Explain. (2 points) Part D: What are the steps you would use to graph f(x)? Justify that you can use …Order of Operations Factors & Primes Fractions Long Arithmetic Decimals Exponents & Radicals Ratios & Proportions Percent Modulo Mean, Median & Mode Scientific Notation Arithmetics. ... (2x^2-1)(-x^2-6) (x^2+2x-1)\cdot(2x^2-3x+6) 4x(4x-2)(x^2-3) Show More; Description. Multiply polynomials step-by-step.Algebra. Factor 4x^2-3x+5. 4x2 − 3x + 5 4 x 2 - 3 x + 5. 4x2 − 3x+5 4 x 2 - 3 x + 5. Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor. Algebra. Find the Roots (Zeros) y=2x^2+3x-5. y = 2x2 + 3x − 5 y = 2 x 2 + 3 x - 5. Set 2x2 +3x− 5 2 x 2 + 3 x - 5 equal to 0 0. 2x2 + 3x−5 = 0 2 x 2 + 3 x - 5 = 0. Solve for x x. Tap for more steps... x = 1,−5 2 x = 1, - 5 2. Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework ... Algebra. Solve by Factoring 2x^2-3x-5=0. 2x2 − 3x − 5 = 0 2 x 2 - 3 x - 5 = 0. Factor by grouping. Tap for more steps... (x+1)(2x −5) = 0 ( x + 1) ( 2 x - 5) = 0. If any individual factor on the left side of the equation is equal to 0 0, the entire expression will be equal to 0 0. x+1 = 0 x + 1 = 0.

Algebra. Solve by Factoring 2x^2+3x-20=0. 2x2 + 3x − 20 = 0 2 x 2 + 3 x - 20 = 0. Factor by grouping. Tap for more steps... (2x−5)(x +4) = 0 ( 2 x - 5) ( x + 4) = 0. If any individual factor on the left side of the equation is equal to 0 0, the entire expression will be equal to 0 0. 2x−5 = 0 2 x - 5 = 0. Step by step solution : Step 1 : Equation at the end of step 1. (2x2 - 3x) - 5 = 0. Step 2 : Trying to factor by splitting the middle term. 2.1 Factoring 2x2-3x-5. The first term is, …Step by Step Solution Step 1 : Equation at the end of step 1 (2x2 - 3x) - 5 Step 2 : Trying to factor by splitting the middle term 2.1 Factoring 2x2-3x-5 The first term is, 2x2 its coefficient is 2 . The middle term is, -3x its coefficient is -3 . The last term, "the constant", is -5…

Reader Q&A - also see RECOMMENDED ARTICLES & FAQs. If $(x+1)$ is a factor, then by Remainder theorem... sum of even powe. Possible cause: #2x^3-3x^2-2x+3# First, start off by factoring the first two terms. #x^2(2.